AC^2=AB^2+BC^2-2AB*BCcosB
BD^2=BC^2+CD^2-2BC*CD*cosC
AC^2+BD^2=AB^2+BC^2-2AB*BCcosB + BC^2+CD^2-2BC*CD*cosC
= AB^2+BC^2+ BC^2+CD^2- 2BC(ABcosB +CD*cosC)
∵AB=CD,BC=AD,∠B+∠C=180°
∴AC^2+BD^2= AB^2+BC^2+ AD^2+CD^2- 2BC(ABcosB +ABcos(180°-B))
= AB^2+BC^2+ AD^2+CD^2- 2BC(ABcosB -ABcosB)
= AB^2+BC^2+ AD^2+CD^2,得证