Question

已知a^2-3a+1=0,求2a^2-5a-2+3/1+a^2.含泪跪求啊!急死人了

Answer 1

a²-3a+1=0

则2a²-6a+2=0

2a²-5a=a-2

a²+1=3a

原式=a-2-2+3/3a

=a-4+1/a

=(a²+1-4a)/a

=(3a-4a)/a

=-a/a

=-1