以下拷贝加整理(我见到两种答案,下面这种居多):
∵四边形ABCD是菱形
∴AD‖BC
∴∠DAE=∠AEB、∠B+∠BAD=180°
∵AB=AE
∴∠AEB=∠B
∴∠B=∠DAE
又∵∠DAE=∠EAF+∠DAF=60°+∠DAF
∴∠B=60°+∠DAF
又由题意易证得△ABE≌△ADF
∴∠BAE=∠DAF
∴∠BAD=60°+∠DAF+∠BAE=60°+2∠DAF
则∠B+∠BAD=60°+∠DAF+60°+2∠DAF=180°
解得∠DAF=20°
则∠B=∠D=80° ∠BAD=∠C=100°