tanx.sinx/tanx-sinx=tanx+sinx/tanxsinx

1个回答

  • 1-cos ^2x=sin^2x 方程两边同时乘以sinx^2/cosx^2

    sin^2x/cos^2x - sin^2x =sin^2x sin^2x/cos^2x

    tan^2x -sin^2x =sin^2 x tan^2 x

    (tanx-sinx)(tanx+sinx)=(sinx tanx) (sinx tanx)

    divide both sides by sinxtanx/(tanx+sinx)

    tanx-sinx/tanx sinx=tanxsinx/tanx+sinx

    tanxsinx/tanx+sinx = tanx-sinx/tanx sinx

    所以,相等

    tanx.sinx/tanx-sinx=tanx+sinx/tanxsinx