(2222)^2=2^2*(1111)^2>(1111)^2
M的3次方+2M2次方+1997
=m(M的2次方 +M-1)+M的2次方 +M-1+1998
=1998
168-100=68=2*34=4*17
156
19991998=x
x^2/( (x-1)^2+(x+1)^2-2 )
=1/2
(2222)^2=2^2*(1111)^2>(1111)^2
M的3次方+2M2次方+1997
=m(M的2次方 +M-1)+M的2次方 +M-1+1998
=1998
168-100=68=2*34=4*17
156
19991998=x
x^2/( (x-1)^2+(x+1)^2-2 )
=1/2