解二元一次方程:降次 (1)x^2-4x+1=0. (2)3x^2-3x-6=0. (3)2x^2-4x-2.5=0.

4个回答

  • (1)x^2-4x+1=0

    ( x^2-4x+4-4)+1=0

    (x-2)^2-4+1=0

    (x-2)^2=3

    x=2±√3

    (2) 3x^2-3x-6=0.

    x^2- x-2=0

    x^2- x+ 1/4 - 1/4 -2=0

    ( x - 1/2 )^2 =9/4

    x=2 x=-1

    (3) 2x^2-4x-2.5=0.

    x^2-2x-2.5/2=0.

    x^2-2x +1 -1=2.5/2

    (x-1)^2=1.25+1=2.25

    x=1+ √2.25 x= 1-√2.25

    (4) (x-1)^2-2(x-1)-3=0 ..

    (x-1)^2-2(x-1) +1 -1 -3=0

    {(x-1)-1}^2=4

    (x-2)^2=4

    x=0 x=4

    5.设这个百分比为q.

    则 360×q×q=100

    q=√10/6 ≈ 5.27 √10 (根10≈3.16)

    所以该商场打5.27折

    6.由题意得:3t^2+8t=16 t﹥0

    t^2+8/3 t=16/3

    t^2+8/3 t +16/9 -16/9 =16/3

    (t+ 4/3)^2 -16/9 =16/3

    t + 4/3= 8/3

    t=4/3

    全部是用同样的方法去组合 (a±1)^2=a^2±2a+1 的公式