设 竖直 速度为 v 水平速度为 u
总速度 V²=v²+u²
u*t=10m
g*t/2=v
（这两个懂吧...）
求出 u*t=5*g=49
V²=v²+u²≥2vu=2*49=98
V最小值=7倍根号2
从物理常识理解就是 45度角向前跳最远 要求的速度也最小
原题：A grey kangaroo can leap a distance of 10 m on horizontal
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