Question

已知loga x=2,logb x=1,logc x=4,则logx (abc)=?

Answer 1

logx (abc)= logx a + logx b + logx c

= 1/(loga x) + 1/(logb x) + 1/(logc x)

= 1/2 + 1/1 + 1/4

= 7/4