F(A,B,C)=A'B+B'C+B'C'=A'B+B'(C+C')=A'B+B'=A'+B'
F(A,B,C)=A'B+B'C+B'C'=∑m(2,3)+∑m(1,5)+∑m(0,4)=∑m(0,1,2,3,4,5)=∑m(0,1,2,3)+∑m(0,1,4,5)=A'+B'
F(A,B,C)=A'B+B'C+B'C'=A'B+B'(C+C')=A'B+B'=A'+B'
F(A,B,C)=A'B+B'C+B'C'=∑m(2,3)+∑m(1,5)+∑m(0,4)=∑m(0,1,2,3,4,5)=∑m(0,1,2,3)+∑m(0,1,4,5)=A'+B'