连接BD,由平行四边形的对称性可知:
S△PAD+S△PCB= 0.5S□ABCD=S△ABD,
即,S△PAD+S△PCB=S△ABD
∴ S△ABD-S△PAD=S△PBC
则,
S△PBD=S△ABD-S△PAD-S△PAB
=S△PBC-S△PAB
=7-2
=5
所以,三角形PBD的面积为5
连接BD,由平行四边形的对称性可知:
S△PAD+S△PCB= 0.5S□ABCD=S△ABD,
即,S△PAD+S△PCB=S△ABD
∴ S△ABD-S△PAD=S△PBC
则,
S△PBD=S△ABD-S△PAD-S△PAB
=S△PBC-S△PAB
=7-2
=5
所以,三角形PBD的面积为5