Question

已知：x²－2x＋y²＋6y＋10＝0,求x＋y的值.

Answer 1

x²－2x＋y²＋6y＋10＝0

(x-1)²+(y+3)²=0

x-1=0,y+3=0

得x=1,y=-3

x+y=1+(-3)=-2