四个
秩为2,则得到的
x1=a1*x3+a2*x4+a3*x5+a4*x6
x2=b1*x3+b2*x4+b3*x5+b4*x6
x3=x3+0*x4+0*x5+0*x6
x4=0*x3+x4+0*x5+0*x6
x5=0*x3+0*x4+x5+0*x6
x6=0*x3+0*x4+0*x5+x6
所以基础解系含有四个解向量[a1 b1 1 0 0 0]',[a2 b2 0 1 0 0],[a3 b3 0 0 1 0],[a4 b4 0 0 0 1]
四个
秩为2,则得到的
x1=a1*x3+a2*x4+a3*x5+a4*x6
x2=b1*x3+b2*x4+b3*x5+b4*x6
x3=x3+0*x4+0*x5+0*x6
x4=0*x3+x4+0*x5+0*x6
x5=0*x3+0*x4+x5+0*x6
x6=0*x3+0*x4+0*x5+x6
所以基础解系含有四个解向量[a1 b1 1 0 0 0]',[a2 b2 0 1 0 0],[a3 b3 0 0 1 0],[a4 b4 0 0 0 1]