令t=√x,dt=dx/2t；
=∫e^x(2x+1)/(2√x) dx=∫e^(t^2)(2t^2+1) dt=∫e^(t^2) dt+∫2t^2*e^(t^2) dt=∫e^(t^2) dt+∫t*[e^(t^2) d(t^2)]
=∫e^(t^2) dt+[t*e^(t^2)-∫e^(t^2)* dt]=t*e^(t^2)+C
=C+√x*e^x
积分∫e^x(2x+1)/2√x
令t=√x,dt=dx/2t；
=∫e^x(2x+1)/(2√x) dx=∫e^(t^2)(2t^2+1) dt=∫e^(t^2) dt+∫2t^2*e^(t^2) dt=∫e^(t^2) dt+∫t*[e^(t^2) d(t^2)]
=∫e^(t^2) dt+[t*e^(t^2)-∫e^(t^2)* dt]=t*e^(t^2)+C
=C+√x*e^x