Question

一个高一的指数函数的题(m-n)/[m^(1/3)-n^(1/3)] - (m+n)/[m^(1/3)+n^(1/3)]

Answer 1

(m-n)/[m^(1/3)-n^(1/3)] - (m+n)/[m^(1/3)+n^(1/3)] 因为(x^3-y^3)/(x-y)=x^2+xy+y^2(x^3+y^3)/(x+y)=x^2-xy+y^2所以原式=[m^(1/3)]^2+m^(1/3)*n^(1/3)+[n^(1/3)]^2-{[m^(1/3)]^2-m^(1/3)*n^(1/3)+[n^(1/3)]^2}=2m^...