(6x²-4x-3)+(x²+4x+1)
= 7x²-2
计算：(6x^2-4x-3)+(x^2+4x+1)
1个回答
相关问题
-
计算3(2x+1)(2x-1)-4(3x-2)(3x+2)+6x(4x+1)
-
计算：[2x-6x2-4x+4÷12-4xx2+x-6•1/x+3]．
-
计算x2+2x+4x2+4x+4÷x3−83x+6÷1x2−4.
-
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
-
计算3x(x-4)^2-6x^2(4-x)
-
1.计算1/6x-4y +1/6x+4y — 3x/4y^2-9x^2
-
计算①x²-4／x²-4x+3÷x²+3x+2／x²-x②2x+6／4-4x+x
-
计算：[2x−6/x−2÷x−3x2−4x+4]．
-
2(x+5)(x+4)-3(x-6)(x+1)计算
-
计算(6x^2-4x)/(3x-2)