a²+b²-6ab=0
a²+b²=6ab
[(a+b)/(b-a)]²
=(a+b)²/(b-a)²
=(a²+2ab+b²)/(a²-2ab+b²)
=(6ab+2ab)/(6ab-2ab)
=8ab/(4ab)
=2
∵a>b>0
∴(a+b)/(b-a)
a²+b²-6ab=0
a²+b²=6ab
[(a+b)/(b-a)]²
=(a+b)²/(b-a)²
=(a²+2ab+b²)/(a²-2ab+b²)
=(6ab+2ab)/(6ab-2ab)
=8ab/(4ab)
=2
∵a>b>0
∴(a+b)/(b-a)