1.a(n+1)^2=2an^2+ana(n+1)数列各项均为正,an≠0,等式两边同除以an^2[a(n+1)/an]^2=2+[a(n+1)/an][a(n+1)/an]^2-[a(n+1)/an]-2=0[a(n+1)/an +1][a(n+1)/an -2]=0a(n+1)/an +1恒>0,要等式成立,只有a(n+1)/an-2=0a(n+1...
数学数列难题已知各项均为正的数列{an},满足(an+1)∧2=2(an)∧2+an×an+1,且a2+a4=2a3+4
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