Question

把多项式写成:x^2+2x-3=(x-1)(mx+n).求m,n的值

Answer 1

(x -1)(mx + n) = mx² + nx - mx -n

= mx² + ( n -m)x -n

因为:x² + 2x - 3 = (x - 1)(mx +n)

所以有:x² + 2x - 3 = mx² + ( n -m)x - n

比较等式两边得:m = 1 n - m = 2

因此,所求m,n 的值是 m = 1 n = 3