MATLAB作业题
> syms x>> limit((2*x^2-2)/(x-1"}}}'>

2个回答

  • 1、ezplot('x^2/5^2+y^2/2^2=1')

    axis equal

    2(1)>> syms x

    >> limit((2*x^2-2)/(x-1),1)

    ans =

    4

    2(2)>> limit((x^2+4)/(x-7),2)

    ans =

    -8/5

    2(3)>> limit((x^2-1)/(x^3-1),1)

    ans =

    2/3

    2(4)>> limit((x^2+3)/(4*x^2-7),inf)

    ans =

    1/4 2(5)>> limit(sqrt(x^2+x)-sqrt(x^2-1),inf)

    ans =

    1/23(1)>> syms x y

    >> z=x*log(x+y);

    >> diff(z,x,2)

    ans =

    2/(x + y) - x/(x + y)^2

    >> diff(z,y,2)

    ans =

    -x/(x + y)^2

    >> diff(diff(z,x),y)

    ans =

    1/(x + y) - x/(x + y)^2 3(2)>> y=solve('x*y+x+y=1','y')

    y =

    -(x - 1)/(x + 1)

    >> diff(y,x)

    ans =

    (x - 1)/(x + 1)^2 - 1/(x + 1)

    3(3)>> syms x y z

    >> F=x/z-log(z/y);

    >> diff(F,x)/diff(F,z)

    ans =

    -1/(z*(x/z^2 + 1/z))

    >> diff(F,y)/diff(F,z)

    ans =

    -1/(y*(x/z^2 + 1/z))