求lim(n→∞)时[5^n-4^(n-1)]/5

求lim(n→∞)时[5^n-4^(n-1)]/5^(n+1)+3^(n+2)

2个回答

求极限 lim(n→∞)[根号(n^2+4n+5)-(n-1)] =
lim [√(3n+1)-√(3n)] /[√(5n+1)-√(5n)]
计算1：lim(n→∞) [5^(n+1)+3^(n+1)] /[5^n+3^n]
求解lim(5n²+3n+1)/(n³+n²+5)
求lim(4n^2-5n-1)÷（7+2n-8n^2）
求1.lim(3n-(3n^2+2n)/(n-1)) 2.lim(8+1/(n+1)) 3.lim根号n(根号(n+1)
lim(n->无穷)[(1+3+5+.(2n+1)]/n^2]^(3-2n)
lim(n+1)(n+2)(n+3)/5n^3 n趋于无穷
lim(2/2*3*4+2/3*4*5+...2/(n+1)(n+2)(n+3)) n→oo
lim(n-无穷)=3n^2/5n^2+2n-1,