Question

用洛必达定理求极限limx→-1根号π-根号arccosx/根号x+1

Answer 1

lim(√π-√arccosx)/(√(x+1))

=lim(1/2)(arccosx)^(-1/2)(1/√(1-x^2))/(1/2√(x+1))

=(1/2)(1/√π)(1/2)*2

=1/(2√π)