n(H2)=V/Vm=2.24/22.4=0.1mol
Fe+H2SO4=FeSO4+H2↑
1 1 1
0.1mol 0.1mol 0.1mol
Fe2O3+3H2SO4=Fe2(SO4)3+3H2O
1 3 1
x 3x x
Fe+Fe2(SO4)3=3FeSO4
1 1
x x
因为铁和氧化铁一共48.8克,则:56×0.1+56x+160x=48.8
解得:x=0.2mol
所以:m(Fe)=0.1×56+56×0.2=16.8g
m(Fe2O3)=0.2×160=32g
n(H2SO4)=0.1+3*0.2=0.7mol
c(H2SO4)=n/V=0.7/0.8=0.875mol/L