Question

当x=2^999,y=(-2)^999时,代数式4x^2-8xy+4y^2的值为

Answer 1

4x^2-8xy+4y^2

=4(x^2-2xy+y^2)

=4(x-y)^2

=4(2^999-(-2)^999)^2

=4*(*2^999)^2

=4*(2^1000)^2

=4^2*2^2000

=2^(2002)