Question

已知x,y满足(x+1)^4+丨y-2丨=0,求-2xy×3x^2y+(1/2 x^2 y^2)×2x+5xy的值

Answer 1

∵(x+1)^4+丨y-2丨=0

∴x+1=0 y-2=0

∴x=-1 y=2

∴-2xy×3x^2y+(1/2 x^2 y^2)×2x+5xy

=-6x³y²+x³y²+5xy

=-5x³y²+5xy

=-5×(-1)³×2²+5×(-1)×2

=20-10

=10