Question

不改变分式的值,使下列分子与分母都不含-号

Answer 1

（1-0.5a)/(a+1/3)

= [(2-a)/2]/[（3a+1）/3]

=[3(2-a)]/[2（3a+1）]

=(6-3a)/(6a+2)

(a^2-0.2a)/(a^2-0.3a^3)

= (a-0.2)/(a-0.3a^2)

= [(5a-1)/5]/[(10a-3a^2)/10]

=(10a-2)/(10a-3a^2)