已知x/2=y/3=z/-1≠0,求分式2x+6y - 知识问答

已知x/2=y/3=z/-1≠0,求分式2x+6y-3z/x+y+2z的值

1个回答

设 x/2=y/3=z/-1=a
x=2a y=3a z=-a
(2x+6y-3z)/(x+y+2z)
=(4a+18a+3a)/(3a)
=25a/3a
=25/3

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