计算.1.3y²分之2x²×6x分之5y÷21x的平方分之10y.​

1个回答

  • 1.3y²分之2x²×6x分之5y÷21x的平方分之10y

    =(3y² × 6x ×10y)分之(2x² × 5y × 21x²)

    =6y²分之7x³

    2.9-x²分之x²-6x+9÷x²+3x分之2x-6

    =(3+x)(3-x)分之(x-3)² × 2(x-3)分之x(x+3)

    =-x/2

    3.2ab分之4a²+4ab+b²×6a+3b分之2a²b.

    =2ab分之(2a+b)² × 3(2a+b)分之2a²b

    =a(2a+b)/3

    =(2a²+ab)/3

    4已知X-3Y=0,求x²-2xy+y²分之2x+y ×(x-y)

    X-3Y=0

    则,x=3y

    x²-2xy+y²分之2x+y ×(x-y)

    =(x-y)² 分之 (2x+y)(x-y)

    =(x-y)分之 (2x+y)

    =(3y-y)分之 (6y+y)

    =2y分之7y

    =2分之7