Question

解两道方程题；1/2[x-1/2(x+1)]=2/3 (x-1) 1/3(x-1)+1/4(x-1)-1/2(x-1)=

Answer 1

1/2[x-1/2(x+1)]=2/3 (x-1)

1/2[x-1/2x-1/2)]=2/3 (x-1)

1/4[x-1]=2/3 (x-1)

1/4[x-1]-2/3 (x-1)=0

(1/4-2/3)[x-1]=0

x-1=0

x=1

1/3(x-1)+1/4(x-1)-1/2(x-1)=1

(1/3+1/4-1/2)(x-1)=1

1/12 (x-1)=1

x-1=12

x=13