设a=m³,b=n³
∴a^2/3+b^2/3=4,即m²+n²=4
x=a+3a^1/3b^2/3,即x=m³+3mn²
y=b+3a^2/3b^1/3,即y=n³+3m²n
∴x+y=m³+3mn²+n³+3m²n=(m+n)³
x-y=m³+3mn²-n³-3m²n=(m-n)³
∴(x+y)^2/3+(x-y)^2/3
=(m+n)²+(m-n)²
=2(m²+n²)
=8
【紧急求助】a^2/3+b^2/3=4,x=a+3a^1/3b^2/3,y=b+3a^2/3b^1/3,求(x+y)^2
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