∫1/(x^2+5x+6)dx
=∫[x+3-(x+2)]/(x^2+5x+6)dx
=∫[1/(x+2)-1/(x+3)]dx
=∫1/(x+2)dx-∫[/(x+3)dx
=ln(x+2)-ln(x+3)
∫1/(x^2+5x+6)dx
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