sin²π/8 -cos²π/8
1个回答
sin²(π/8) -cos²(π/8)
=-cos(2*π/8)
=-cos(π/4)
=-√2/2
相关问题
(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）.
sin*2π/8+cos*27π/24+sinπ/8cos7π/24
计算：cos（π/8）*sin（π/8）=?
sin^4π/8-cos^4π/8=?
cos(3π/8)*sin(5π/8)=?
cos2π8-sin2π8= ___ ．
f(x)=1-2sin^2(x+π/8)+2sin(x+π/8)*cos(x+π/8)=cos(2x+π/4)+sin(
cos^4π/8sin^4π/8等于
-3sinπ/8cosπ/8 化简
求值-cosπ/16sinπ/16cosπ/8