Question

给定直线：y=2x-16抛物线：y^2=ax(a>0)当抛物线的焦点在直线上L时,

Answer 1

1.y^2=ax(a>0)的焦点坐标为（a/4 .0)

2.因为抛物线的焦点在直线L上,所以把（a/4 .0)代入y=2x-16

3.可以求得a=32

4.C:y^2=32x