AD=CD DAC=C设 DAC=C=x
ADB=2x
AB=BD ADB=BAD=2x BAC=DAC+BAD=3x
AB=AC B=C=x
BAC+B+C=5x=180 x=36
B=C=CAD=36
故ABC相似DAC
AC/CD=BC/AC=(BD+CD)/AC
BD/CD=(BD+CD)/BD
BD/AC=(根5+1)/2
AD=CD DAC=C设 DAC=C=x
ADB=2x
AB=BD ADB=BAD=2x BAC=DAC+BAD=3x
AB=AC B=C=x
BAC+B+C=5x=180 x=36
B=C=CAD=36
故ABC相似DAC
AC/CD=BC/AC=(BD+CD)/AC
BD/CD=(BD+CD)/BD
BD/AC=(根5+1)/2