(x²+2x+1)/(x-2)÷(x²-1)/(x-1)+1/(2-x)
=(x+1)²/(x-2)÷[(x+1)(x-1)]/(x-1)-1/(x-2)
=(x+1)²/(x-2)÷(x+1)-1/(x-2)
=(x+1)/(x-2)-1/(x-2)
=[(x+1)-1]/(x-2)
=x/(x-2)
当x=3时,原式=3/(3-2)=3
请点击下面的【选为满意回答】按钮.
(x²+2x+1)/(x-2)÷(x²-1)/(x-1)+1/(2-x)
=(x+1)²/(x-2)÷[(x+1)(x-1)]/(x-1)-1/(x-2)
=(x+1)²/(x-2)÷(x+1)-1/(x-2)
=(x+1)/(x-2)-1/(x-2)
=[(x+1)-1]/(x-2)
=x/(x-2)
当x=3时,原式=3/(3-2)=3
请点击下面的【选为满意回答】按钮.