Question

（x+3）分之1-（x^2-9）分之6-（3-x）分之1

Answer 1

（x+3）分之1-（x^2-9）分之6-（3-x）分之1

=（x+3）分之1-（x^2-9）分之6+（x-3）分之1

=(x-3-6+x+3)/(x+3)(x-3)

=(2x-6)/(x+3)(x-3)

=2/(x+3)