Question

y=(1+sinx)/cosx,求导是不是等于（sinx+1）/(cos^2)x

Answer 1

y=(1+sinx)/cosx

y'=[(1+sinx)/cosx]'

=[cosx*cosx-(1+sinx)*(-sinx)]/cos^2x

=（sinx+1）/cos^2x

你算的是对的啊!恭喜恭喜!