ln|(cosx-1)/(cosx+1)|=ln|(1-cosx)/(1+cosx)|=ln|(1-cosx)²/[(1+cosx)(1-cosx)]|=ln|(1-cosx)²/sin²x|=2ln|(1-cosx)/sinx|=2ln|1/sinx-cosx/sinx|=2ln|cscx-cotx|
ln/cos x-1/cos x+1/如何化简为ln/csc x-cot x/
1个回答
相关问题
-
lim[cos ln(1+x)-cos ln(x)]
-
对数化简[ ln(1-2x) ] / [ ln(1-x) ] 还能继续化简吗?还有 ln( (1-2x)/(1-x) )
-
lim x→0 ln(cos5x)/ln(cos2x)
-
化简求值:1/2ln(2x+2√(x^2-1))+ln(√(x+1)-√(x-1)) 2x
-
化简:cos^2x / ( cot(x/2)-tan(x/2) )
-
ln x/(x+1)+(1/x)-[(ln x)/(x-1)]怎么化成【1/(1-x方)】*【2ln x-(x方-1)/
-
f (x) = ∫[a sin(ln x) + b cos(ln x)]dx
-
求极限:lim(x→0)ln(1+x²)/ (sec x- cos x)
-
高等数学〔工专〕ln〔-x+√〔1+〔-x〕^2〕〕=ln〔1/〔〔x+√〔1+x^2〕〕〕〕如何从 ln〔-x+√〔1
-
ln(cos x)/ (cos x)²求积分怎么解?