f'(x)=2x
P(p,p^2)
l1与l2的夹角为θ,则tanθ=|(k2- k1)/(1+ k1k2)|
k2=3 k1=p
1=|(3-p)/(1+p*3)|
(3-p)/(1+p*3)=1 p=1/2
(3-p)/(1+p*3)=-1 p=2
P1(1/2,1/4) P2(2,4)
f'(x)=2x
P(p,p^2)
l1与l2的夹角为θ,则tanθ=|(k2- k1)/(1+ k1k2)|
k2=3 k1=p
1=|(3-p)/(1+p*3)|
(3-p)/(1+p*3)=1 p=1/2
(3-p)/(1+p*3)=-1 p=2
P1(1/2,1/4) P2(2,4)