Question

y=|x+1|/x^2+2求函数最大值

Answer 1

当x=1

则x=t-1

y=t/[t^2-2t+1+2]=t/(t^2-2t+3)

1/y=t+3/t-2

由均值不等式,t+3/t>=2√(t*3/t)=2√3,当t=3/t即t=√3时取等号,此时x=√3-1

所以1/y>=2√3-2

得y