因为∠AOD=∠AOB+∠BOD
所以∠AOD+∠BOD=∠AOB+2∠BOD
即1/2(∠AOD+∠BOD)=1/2(∠AOB+2∠BOD)=1/2∠AOB+∠BOD
因为∠AOB=2∠COB 即∠COB=1/2∠AOB
所以∠COD=∠COB+∠BOD=1/2∠AOB+∠BOD
所以1/2(∠AOD+BOD)=∠COD
所以答案是相等
因为∠AOD=∠AOB+∠BOD
所以∠AOD+∠BOD=∠AOB+2∠BOD
即1/2(∠AOD+∠BOD)=1/2(∠AOB+2∠BOD)=1/2∠AOB+∠BOD
因为∠AOB=2∠COB 即∠COB=1/2∠AOB
所以∠COD=∠COB+∠BOD=1/2∠AOB+∠BOD
所以1/2(∠AOD+BOD)=∠COD
所以答案是相等