Question

1002^2-1002*4+4896^2+208*896+104^2(181^2-61^2)/(301^2-181^2)

Answer 1

1002^2-1002*4+4 =(1002-2)^2=1000000

896^2+208*896+104^2=(896+104)^2=1000000

(181^2-61^2)/(301^2-181^2)

=(181+61)(181-61)/(301+181)(301-181)

=242x120/482x120

=121/241

x+(1/x)=-3,

两边平方,

x^2+(1/x^2)+2=9

x^2+(1/x^2)=9-2=7