Question

求这到极限题的具体步骤

Answer 1

运用等价无穷小替换,

sinx~x,e^x-1~x,

——》原式=limx→0 (e^x-1-sinx)/x^2

=limx→0 (e^x-cosx)/2x,

=limx→0 (e^x+sinx)/2,

=(e^0+sin0)/2,

=1/2.