lim1/n[(1+1/2)(1+1/3)(1+1

lim1/n[(1+1/2)(1+1/3)(1+1/4)…(1+1/n)]=_____

1个回答

[(1+1/2)(1+1/3)(1+1/4)…(1+1/n)]
=(3/2)(4/3).(n+1)/n=(n+1)/2
lim1/n[(1+1/2)(1+1/3)(1+1/4)…(1+1/n)]
=lim(n+1)/2n
=1/2

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