lim(√(n^2-1) -n)/(n-√(n^2+1))
=lim(√(n^2-1) -n)(√(n^2-1) +n)(n+√(n^2+1))/[(n-√(n^2+1))(n+√(n^2+1))(√(n^2-1) +n)]
=lim-(n+√(n^2+1)/[-(√(n^2-1) +n)]
=lim(1/n+√(1/n^2+1)/[(√(1-1/n^2) +1/n)]
=1/1
=1
求极限lim(√(n^2-1) -n)/(n-√(n^2+1))的值
2个回答
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