第一列-3×第二列+3×第三列-第四列=0.
恒等式：x²-3(x+1)²+3(x+2)²-(x+3)²=0.
x²-3(x+1)²+3(x+2)²-(x+3)²
=x²-(x+3)²+3(x+2)²-3(x+1)²
=(x-x-3)(x+x+3)+3(x+2-x-1)(x+2+x+1)
=-3(2x+3)+3(2x+3)=0.
求证下面的行列式等于0 ｜a^2 (a+1)^2 (a+2)^2 (a+3)^2｜｜b^2 (b+1)^2 (b+2)^
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