(1) 2CaO 2= 2CaO+O 2↑ (2) 80% (3)
(1) 2CaO 2= 2CaO+O 2↑
(2) w (CaO 2)=
×100%=80%
(3) n (CaC 2O 4)= n (Ca 2+)=31.0×10 -3 L×0.0200 mol·L -1×
=0.00155 mol
其中CaO 2所含的 n (Ca 2+)=
=0.00133 mol
m (CaO)=(0.00155 mol-0.00133 mol)×56.0 g·mol -1=0.012 g
m (H 2O)=0.120 g―0.120g×80.0%―0.012 g=0.012 g
∶
=2∶1 x =