已知a=1 b=2,则1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2008)(b+2008)=1/2+1/2*3+1/3*4+1/4*5+1/5*6+.+1/2009*2010=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.-1/2009+1/2009-1/2010=1-1/2010=2009/2010
已知a=1 b=2,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2008)(b+200
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