答:
直线(3a+2)x+(1-4a)y+8=0与(5a-2)x+(a+4)y -7=0垂直
1)
3a+2=0并且a+4=0
无解
2)
1-4a=0并且5a-2=0
无解
3)
k1*k2=-1
[ (3a+2) /(4a-1) ] * [ (2-5a) /(a+4)]=-1
(3a+2)(5a-2)=(4a-1)(a+4)
15a^2+4a-4=4a^2+15a-4
11a^2-11a=0
解得:a=0或者a=1
答:
直线(3a+2)x+(1-4a)y+8=0与(5a-2)x+(a+4)y -7=0垂直
1)
3a+2=0并且a+4=0
无解
2)
1-4a=0并且5a-2=0
无解
3)
k1*k2=-1
[ (3a+2) /(4a-1) ] * [ (2-5a) /(a+4)]=-1
(3a+2)(5a-2)=(4a-1)(a+4)
15a^2+4a-4=4a^2+15a-4
11a^2-11a=0
解得:a=0或者a=1