解析
a²+ab=20
ab-b²=-13
(1)a²+2ab-b²=(a²+ab)+(ab-b²)
=20-13
=7
(2—)a²+3ab-2b²
=(a²+ab)+2ab-2b²
=(a²+ab)+2(ab-b²)
=20+2*-13
=20-26
=-6
解析
a²+ab=20
ab-b²=-13
(1)a²+2ab-b²=(a²+ab)+(ab-b²)
=20-13
=7
(2—)a²+3ab-2b²
=(a²+ab)+2ab-2b²
=(a²+ab)+2(ab-b²)
=20+2*-13
=20-26
=-6