x^3z+4x^2yz+4xy^2z因式分解
2个回答
解x^3z+4x^2yz+4xy^2z
=xz(x²+4xy+4y²)
=xz(x+2y)².
相关问题
5yz/(y+z)=6,4xy/(z+x)=3,3xy/x+y=2
因式分解4x²-y²-2yz+z²
x2+4y2+9z2-4xy-6xz+12yz,因式分解
已知xy/x+y=-2,yz/y+z=4/3,xz/x+z=-4/3,求xyz/xy+yz+xz的
2/x=3/y=4/z,求代数式2x^2-3yz+z^2/x^2-2xy-z^2
因式分解:24xy^2*z^2(x+y-z)-6x^2yz(z-x-y)^2-8xyz^3(x+y-3)
因式分解:24xy^2*z^2(x+y-z)-6x^2yz(z-x-y)^2-8xyz^3(x+y-3)
x/2=y/3=z/4,求(xy+yz+xz)/(x^2+y^2+z^2)
因式分解:x2y+y2z+z2x+xy2+yz2+zx2+3xyz
xy=2x+2y yz=4y+4z zx=5z+5x y=?z=?